# 8.3. Cross-Classifying by More than One Variable#

When individuals have multiple features, there are many different ways to classify them. For example, if we have a population of college students for each of whom we have recorded a major and the number of years in college, then the students could be classified by major, or by year, or by a combination of major and year.

The group method also allows us to classify individuals according to multiple variables. This is called cross-classifying.

## 8.3.1. Two Variables: Counting the Number in Each Paired Category#

The table more_cones records the flavor, color, and price of six ice cream cones.

more_cones = Table().with_columns(
'Flavor', make_array('strawberry', 'chocolate', 'chocolate', 'strawberry', 'chocolate', 'bubblegum'),
'Color', make_array('pink', 'light brown', 'dark brown', 'pink', 'dark brown', 'pink'),
'Price', make_array(3.55, 4.75, 5.25, 5.25, 5.25, 4.75)
)

more_cones

Flavor Color Price
strawberry pink 3.55
chocolate light brown 4.75
chocolate dark brown 5.25
strawberry pink 5.25
chocolate dark brown 5.25
bubblegum pink 4.75

We know how to use group to count the number of cones of each flavor:

more_cones.group('Flavor')

Flavor count
bubblegum 1
chocolate 3
strawberry 2

But now each cone has a color as well. To classify the cones by both flavor and color, we will pass a list of labels as an argument to group. The resulting table has one row for every unique combination of values that appear together in the grouped columns. As before, a single argument (a list, in this case, but an array would work too) gives row counts.

Although there are six cones, there are only four unique combinations of flavor and color. Two of the cones were dark brown chocolate, and two pink strawberry.

more_cones.group(['Flavor', 'Color'])

Flavor Color count
bubblegum pink 1
chocolate dark brown 2
chocolate light brown 1
strawberry pink 2

## 8.3.2. Two Variables: Finding a Characteristic of Each Paired Category#

A second argument aggregates all other columns that are not in the list of grouped columns.

more_cones.group(['Flavor', 'Color'], sum)

Flavor Color Price sum
bubblegum pink 4.75
chocolate dark brown 10.5
chocolate light brown 4.75
strawberry pink 8.8

Three or More Variables. You can use group to classify rows by three or more categorical variables. Just include them all in the list that is the first argument. But cross-classifying by multiple variables can become complex, as the number of distinct combinations of categories can be quite large.

## 8.3.3. Pivot Tables: Rearranging the Output of group#

Many uses of cross-classification involve just two categorical variables, like Flavor and Color in the example above. In these cases it is possible to display the results of the classification in a different kind of table, called a pivot table. Pivot tables, also known as contingency tables, make it easier to work with data that have been classified according to two variables.

Recall the use of group to count the number of cones in each paired category of flavor and color:

more_cones.group(['Flavor', 'Color'])

Flavor Color count
bubblegum pink 1
chocolate dark brown 2
chocolate light brown 1
strawberry pink 2

The same data can be displayed differenly using the Table method pivot. Ignore the code for a moment, and just examine the table of outcomes.

more_cones.pivot('Flavor', 'Color')

Color bubblegum chocolate strawberry
dark brown 0 2 0
light brown 0 1 0
pink 1 0 2

Notice how this table displays all nine possible pairs of flavor and color, including pairs like “dark brown bubblegum” that don’t exist in our data. Notice also that the count in each pair appears in the body of the table: to find the number of light brown chocolate cones, run your eye along the row light brown until it meets the column chocolate.

The group method takes a list of two labels because it is flexible: it could take one or three or more. On the other hand, pivot always takes two column labels, one to determine the columns and one to determine the rows.

pivot

The pivot method is closely related to the group method: it groups together rows that share a combination of values. It differs from group because it organizes the resulting values in a grid. The first argument to pivot is the label of a column that contains the values that will be used to form new columns in the result. The second argument is the label of a column used for the rows. The result gives the count of all rows of the original table that share the combination of column and row values.

Like group, pivot can be used with additional arguments to find characteristics of each paired category. An optional third argument called values indicates a column of values that will replace the counts in each cell of the grid. All of these values will not be displayed, however; the fourth argument collect indicates how to collect them all into one aggregated value to be displayed in the cell.

An example will help clarify this. Here is pivot being used to find the total price of the cones in each cell.

more_cones.pivot('Flavor', 'Color', values='Price', collect=sum)

Color bubblegum chocolate strawberry
dark brown 0 10.5 0
light brown 0 4.75 0
pink 4.75 0 8.8

And here is group doing the same thing.

more_cones.group(['Flavor', 'Color'], sum)

Flavor Color Price sum
bubblegum pink 4.75
chocolate dark brown 10.5
chocolate light brown 4.75
strawberry pink 8.8

Though the numbers in both tables are the same, table produced by pivot is easier to read and lends itself more easily to analysis. The advantage of pivot is that it places grouped values into adjacent columns, so that they can be combined and compared.

## 8.3.4. Example: Education and Income of Californian Adults#

The State of California’s Open Data Portal is a rich source of information about the lives of Californians. It is our source of a dataset on educational attainment and personal income among Californians over the years 2008 to 2014. The data are derived from the U.S. Census Current Population Survey.

For each year, the table records the Population Count of Californians in many different combinations of age, gender, educational attainment, and personal income. We will study only the data for the year 2014.

full_table = Table.read_table(path_data + 'educ_inc.csv')
ca_2014 = full_table.where('Year', are.equal_to('1/1/14 0:00')).where('Age', are.not_equal_to('00 to 17'))
ca_2014

Year Age Gender Educational Attainment Personal Income Population Count
1/1/14 0:00 18 to 64 Female No high school diploma H: 75,000 and over 2058
1/1/14 0:00 65 to 80+ Male No high school diploma H: 75,000 and over 2153
1/1/14 0:00 65 to 80+ Female No high school diploma G: 50,000 to 74,999 4666
1/1/14 0:00 65 to 80+ Female High school or equivalent H: 75,000 and over 7122
1/1/14 0:00 65 to 80+ Female No high school diploma F: 35,000 to 49,999 7261
1/1/14 0:00 65 to 80+ Male No high school diploma G: 50,000 to 74,999 8569
1/1/14 0:00 18 to 64 Female No high school diploma G: 50,000 to 74,999 14635
1/1/14 0:00 65 to 80+ Male No high school diploma F: 35,000 to 49,999 15212
1/1/14 0:00 65 to 80+ Male College, less than 4-yr degree B: 5,000 to 9,999 15423
1/1/14 0:00 65 to 80+ Female Bachelor's degree or higher A: 0 to 4,999 15459

... (117 rows omitted)

Each row of the table corresponds to a combination of age, gender, educational level, and income. There are 127 such combinations in all!

As a first step it is a good idea to start with just one or two variables. We will focus on just one pair: educational attainment and personal income.

educ_inc = ca_2014.select('Educational Attainment', 'Personal Income', 'Population Count')
educ_inc

Educational Attainment Personal Income Population Count
No high school diploma H: 75,000 and over 2058
No high school diploma H: 75,000 and over 2153
No high school diploma G: 50,000 to 74,999 4666
High school or equivalent H: 75,000 and over 7122
No high school diploma F: 35,000 to 49,999 7261
No high school diploma G: 50,000 to 74,999 8569
No high school diploma G: 50,000 to 74,999 14635
No high school diploma F: 35,000 to 49,999 15212
College, less than 4-yr degree B: 5,000 to 9,999 15423
Bachelor's degree or higher A: 0 to 4,999 15459

... (117 rows omitted)

Let’s start by looking at educational level alone. The categories of this variable have been subdivided by the different levels of income. So we will group the table by Educational Attainment and sum the Population Count in each category.

education = educ_inc.select('Educational Attainment', 'Population Count')
educ_totals = education.group('Educational Attainment', sum)
educ_totals

Educational Attainment Population Count sum
Bachelor's degree or higher 8525698
College, less than 4-yr degree 7775497
High school or equivalent 6294141
No high school diploma 4258277

There are only four categories of educational attainment. The counts are so large that is is more helpful to look at percents. For this, we will use the function percents that we defined in an earlier section. It converts an array of numbers to an array of percents out of the total in the input array.

def percents(array_x):
return np.round( (array_x/sum(array_x))*100, 2)


We now have the distribution of educational attainment among adult Californians. More than 30% have a Bachelor’s degree or higher, while almost 16% lack a high school diploma.

educ_distribution = educ_totals.with_column(
'Population Percent', percents(educ_totals.column(1))
)
educ_distribution

Educational Attainment Population Count sum Population Percent
Bachelor's degree or higher 8525698 31.75
College, less than 4-yr degree 7775497 28.96
High school or equivalent 6294141 23.44
No high school diploma 4258277 15.86

By using pivot, we can get a contingency table (a table of counts) of adult Californians cross-classified by Educational Attainment and Personal Income.

totals = educ_inc.pivot('Educational Attainment', 'Personal Income', values='Population Count', collect=sum)
totals

Personal Income Bachelor's degree or higher College, less than 4-yr degree High school or equivalent No high school diploma
A: 0 to 4,999 575491 985011 1161873 1204529
B: 5,000 to 9,999 326020 810641 626499 597039
C: 10,000 to 14,999 452449 798596 692661 664607
D: 15,000 to 24,999 773684 1345257 1252377 875498
E: 25,000 to 34,999 693884 1091642 929218 464564
F: 35,000 to 49,999 1122791 1112421 782804 260579
G: 50,000 to 74,999 1594681 883826 525517 132516
H: 75,000 and over 2986698 748103 323192 58945

Here you see the power of pivot over other cross-classification methods. Each column of counts is a distribution of personal income at a specific level of educational attainment. Converting the counts to percents allows us to compare the four distributions.

distributions = totals.select(0).with_columns(
"Bachelor's degree or higher", percents(totals.column(1)),
'College, less than 4-yr degree', percents(totals.column(2)),
'High school or equivalent', percents(totals.column(3)),
'No high school diploma', percents(totals.column(4))
)

distributions

Personal Income Bachelor's degree or higher College, less than 4-yr degree High school or equivalent No high school diploma
A: 0 to 4,999 6.75 12.67 18.46 28.29
B: 5,000 to 9,999 3.82 10.43 9.95 14.02
C: 10,000 to 14,999 5.31 10.27 11 15.61
D: 15,000 to 24,999 9.07 17.3 19.9 20.56
E: 25,000 to 34,999 8.14 14.04 14.76 10.91
F: 35,000 to 49,999 13.17 14.31 12.44 6.12
G: 50,000 to 74,999 18.7 11.37 8.35 3.11
H: 75,000 and over 35.03 9.62 5.13 1.38

At a glance, you can see that over 35% of those with Bachelor’s degrees or higher had incomes of $$\75,000$$ and over, whereas fewer than 10% of the people in the other education categories had that level of income.

The bar chart below compares the personal income distributions of adult Californians who have no high school diploma with those who have completed a Bachelor’s degree or higher. The difference in the distributions is striking. There is a clear positive association between educational attainment and personal income.

distributions.select(0, 1, 4).barh(0)